what is the quotient of 2m^9n^4/-4m^-3n^-2 in simplest form? assume m=0,n=0 A.-m^-12n^6/2B.-m^27n^8/2C.6m^12n^6D.8m^12n^6
Accepted Solution
A:
Answer:The value of the quotient is [tex]-\frac{m^{12}n^{6}}{2}[/tex].Step-by-step explanation:The given expression is,[tex]\frac{2m^9n^4}{-4m^{-3}n^{-2}}[/tex]We have to find the quotient of the given expression.Use the exponent rule,[tex]\frac{a^n}{a^m} =a^{n-m}[/tex][tex]\frac{2m^9n^4}{-4m^{-3}n^{-2}}=-\frac{m^{9-(-3)}n^{4-(-2)}}{2}[/tex][tex]\frac{2m^9n^4}{-4m^{-3}n^{-2}}=-\frac{m^{9+3}n^{4+2}}{2}[/tex][tex]\frac{2m^9n^4}{-4m^{-3}n^{-2}}=-\frac{m^{12}n^{6}}{2}[/tex]Therefore the value of the quotient is [tex]-\frac{m^{12}n^{6}}{2}[/tex].